Insert node into the middle of the linked list - cook the code

Saturday, 27 January 2018

Insert node into the middle of the linked list


Insert node into the middle of the linked list


Given a linked list containing n nodes. The problem is to insert a new node with data x at the middle of the list. If n is even, then insert the new node after the (n/2)th node, else insert the new node after the (n+1)/2th node.
Examples:
Input : list: 1->2->4->5
        x = 3
Output : 1->2->3->4->5

Input : list: 5->10->4->32->16
        x = 41
Output : 5->10->4->41->32->16
(Using two pointers)

void insertAtMid(Node** head_ref, int x)
{
    // if list is empty
    if (*head_ref == NULL)
        *head_ref = getNode(x);
 
    else {
        // get a new node
        Node* newNode = getNode(x);
 
        // assign values to the slow and fast
        // pointers
        Node* slow = *head_ref;
        Node* fast = (*head_ref)->next;
 
        while (fast && fast->next) {
 
            // move slow pointer to next node
            slow = slow->next;
 
            // move fast pointer two nodes at a time
            fast = fast->next->next;
        }
 
        // insert the 'newNode' and adjust the
        // required links
        newNode->next = slow->next;
        slow->next = newNode;
    }

}

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