Write a program to print all permutations of a given string
A permutation, also called an “arrangement number” or “order,” is a rearrangement of the elements of an ordered list S into a one-to-one correspondence with S itself. A string of length n has n! permutation.
Below are the permutations of string ABC.
ABC ACB BAC BCA CBA CAB
ABC ACB BAC BCA CBA CAB
Here is a solution that is used as a basis in backtracking.
- C/C++
- Java
- Python
// C program to print all permutations with duplicates allowed #include <stdio.h> #include <string.h> /* Function to swap values at two pointers */ void swap( char *x, char *y) { char temp; temp = *x; *x = *y; *y = temp; } /* Function to print permutations of string This function takes three parameters: 1. String 2. Starting index of the string 3. Ending index of the string. */ void permute( char *a, int l, int r) { int i; if (l == r) printf ( "%sn" , a); else { for (i = l; i <= r; i++) { swap((a+l), (a+i)); permute(a, l+1, r); swap((a+l), (a+i)); //backtrack } } } /* Driver program to test above functions */ int main() { char str[] = "ABC" ; int n = strlen (str); permute(str, 0, n-1); return 0; } |
Output:
ABC ACB BAC BCA CBA CAB
Algorithm Paradigm: Backtracking
Time Complexity: O(n*n!) Note that there are n! permutations and it requires O(n) time to print a a permutation.
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